function Y = imfft(X)
Y = fftshift(fft2(X));

### imifft.m - Inverse imFFT.

function Y = imifft(X)
Y = abs(ifft2(ifftshift(X)));

### immagphase.m - Displays magnitude and phase of a matrix containing
imFFT information.

function immagphase(X)
subplot(121)
A = abs(X);
if min(min(A)) == 0
Y = mat2gray(log(A + 1e-7));
else
Y = mat2gray(log(A));
end
subimage([-1 1],[-1 1],Y)
title 'Magnitude'
subplot(122)
Y = mat2gray(angle(X));
subimage([-1 1],[-1 1],Y)
title 'Phase'

### lowpassfilter.m - Creates lowpass Butterworth filter in two dimensions.

% LOWPASSFILTER - Constructs a low-pass butterworth filter.
%
% usage: f = lowpassfilter(sze, cutoff, n)
%
% where: sze is a two element vector specifying the size of filter
% to construct.
% cutoff is the cutoff frequency of the filter 0 - 0.5
% n is the order of the filter, the higher n is the sharper
% the transition is. (n must be an integer >= 1).
%
% The frequency origin of the returned filter is at the corners.
%
% See also: HIGHPASSFILTER, HIGHBOOSTFILTER, BANDPASSFILTER
%
% Peter Kovesi pk@cs.uwa.edu.au
% Department of Computer Science & Software Engineering
% The University of Western Australia
%
% October 1999
%
% Modified Rob Gaddi gaddi@rice.edu
% ELEC 301
% Rice University
%
% December 2001
function f = lowpassfilter(sze, cutoff, n)
if cutoff < 0 | cutoff > 0.5
error('cutoff frequency must be between 0 and 0.5');
end
if rem(n,1) ~= 0 | n < 1
error('n must be an integer >= 1');
end
% Modification ELEC 301 Project Group, Dec 2001
% Original code [rows, cols] = sze was not accepted by Matlab
rows = sze(1);
cols = sze(2);
% End Alteration
% X and Y matrices with ranges normalised to +/- 0.5
x = (ones(rows,1) * [1:cols] - (fix(cols/2)+1))/cols;
y = ([1:rows]' * ones(1,cols) - (fix(rows/2)+1))/rows;
radius = sqrt(x.^2 + y.^2); % A matrix with every pixel = radius relative to centre.
% Alteration, ELEC 301 Project Group, Dec 2001
% Original code fftshifted the filter before output. Since
% imFFT and imIFFT already shift, the output should remain low-centered.
f = 1 ./ (1.0 + (radius ./ cutoff).^(2*n)); % The filter
% End Alteration

### bandpassfilter.m - Creates bandpass Butterworth filter in two dimensions.

% BANDPASSFILTER - Constructs a band-pass butterworth filter
%
% usage: f = bandpassfilter(sze, cutin, cutoff, n)
%
% where: sze is a two element vector specifying the size of filter
% to construct.
% cutin and cutoff are the frequencies defining the band pass 0 - 0.5
% n is the order of the filter, the higher n is the sharper
% the transition is. (n must be an integer >= 1).
%
% The frequency origin of the returned filter is at the corners.
%
% See also: LOWPASSFILTER, HIGHPASSFILTER, HIGHBOOSTFILTER
%
% Peter Kovesi pk@cs.uwa.edu.au
% Department of Computer Science & Software Engineering
% The University of Western Australia
%
% October 1999
function f = bandpassfilter(sze, cutin, cutoff, n)
if cutin < 0 | cutin > 0.5 | cutoff < 0 | cutoff > 0.5
error('frequencies must be between 0 and 0.5');
end
if rem(n,1) ~= 0 | n < 1
error('n must be an integer >= 1');
end
f = lowpassfilter(sze, cutoff, n) - lowpassfilter(sze, cutin, n);

### highpassfilter.m - Creates highpass Butterworth filter in two dimensions.

% HIGHPASSFILTER - Constructs a high-pass butterworth filter.
%
% usage: f = highpassfilter(sze, cutoff, n)
%
% where: sze is a two element vector specifying the size of filter
% to construct.
% cutoff is the cutoff frequency of the filter 0 - 0.5
% n is the order of the filter, the higher n is the sharper
% the transition is. (n must be an integer >= 1).
%
% The frequency origin of the returned filter is at the corners.
%
% See also: LOWPASSFILTER, HIGHBOOSTFILTER, BANDPASSFILTER
%
% Peter Kovesi pk@cs.uwa.edu.au
% Department of Computer Science & Software Engineering
% The University of Western Australia
%
% October 1999
function f = highpassfilter(sze, cutoff, n)
if cutoff < 0 | cutoff > 0.5
error('cutoff frequency must be between 0 and 0.5');
end
if rem(n,1) ~= 0 | n < 1
error('n must be an integer >= 1');
end
f = 1.0 - lowpassfilter(sze, cutoff, n);

### EFilter.m - Generates a Butterworth bandpass filter of any
elliptical shape.

%EFILTER constructs an elliptical lowpass filter Butterworth filter
% E = EFILTER(Size, cutoffM, cutoffm, n) designs an Nth order elliptical
% lowpass digital Butterworth filter where Size is a two element
% [rows, cols] vector specifying the size of the filter to construct,
% cutoffM and cutoffm, the cutoff freqency on the major and minor
% axes are 0 < cutoff <= 1.
%
% If E = EFilter(Size, cutoffM, cutoffm, n, alpha), where alpha is an angle
% in radians, it will return and plot an elliptical filter rotated
% counter-clockwise through alpha.
%
% If E = EFilter(Size, cutoffM, cutoffm, n, alpha, xoff, yoff), where xoff
% and yoff are offsets in the x and y direction, it will return and
% plot an eliptical filter which is offset by the specified amount.
% An offset of 0 corresponds to the center and an offset of 1
% corresponds to the edge of the filter. A positive offset shifts the
% filter in the positive direction.
%
% Calling EFilter(...) without assigning the output variable
% plots the 3D surface described by the function.
% Katie Streit kstreit@rice.edu
% ELEC 301
% Rice University
%
% December 2001
% Much of this code was based on Peter Kovesi's (pk@cs.uwa.edu.au)
% Matlab function for a lowpass Butterworth filter.
function varargout = EFilter(sze, cutoffM, cutoffm, n, varargin);
if nargin == 4
alpha = 0;
offx = 0;
offy = 0;
elseif nargin == 5
offx = 0;
offy = 0;
alpha = varargin{1};
elseif nargin == 7
alpha = varargin{1};
offx = varargin{2};
offy = varargin{3};
else
error('Invalid number of input arguments');
end
if nargout > 1
error('Invalid number of output arguments');
end
if cutoffM < 0 | cutoffM > 1
error('cutoffM frequency must be between 0 and 1');
end
if cutoffm < 0 | cutoffm > 1
error('cutoffm frequency must be between 0 and 1');
end
if rem(n,1) ~= 0 | n < 1
error('n must be an integer >= 1');
end
%%extracts the sizes from sze
rows = sze(1);
cols = sze(2);
%x and y matrices normalized to +/-.5 and an offset of offx or offy
x = ((((ones(rows,1) * [1:cols])-offx*rows/2) - (fix(cols/2)+1))/cols);
y = ((([1:rows]' * ones(1,cols))-offy*rows/2) - (fix(rows/2)+1))/rows;
%applies a linear transformation to rotate through alpha. Note that it takes
% uses negative alpha, which is caused by x and y being independent matrices.
x2 = (x*cos(alpha) - y*sin(-alpha));
y2 = (x*sin(-alpha) + y*cos(alpha));
%constructs an elliptical cone (defined by a and b) of height r on each at
%each elliptical ring. (r is effectively the "radius")
%r = sqrt(((x2/a).^2 + (y2/b).^2));
%Designs the filter
%f = 1./(1.0 + (r./cutoff).^(2*n));
a = cutoffM/2;
b = cutoffm/2;
f = 1./(1+((x2/(a)).^2 + (y2/(b)).^2).^n);
if nargout > 0
varargout{1} = f;
else
%Plots a normalized (+/- 1), interpolated 3D image of the filter
surf([-1:2/(cols-1):1],[-1:2/(rows-1):1], f);
shading interp;
title('Elliptical Butterworth filter');
xlabel('x');
ylabel('y');
zlabel('intensity');
grid on;
end